earning com/ibiscms/mod/ibis/view.php?id 3142802 o Bowie State University --x He

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earning com/ibiscms/mod/ibis/view.php?id 3142802 o Bowie State University --x Help urrent Documents D Suggested sites DC Council Live d Department of sm. e Dc Code Code of the Di HR e start t e Print calculator Periodic Table Question 21 of 28 Incorrect Incorrect Sapling Learning A boy his down a at a height of 1.01 m above the bottom of the chute and with an initial speed of 1.57 m/s. The toy animal horizontally from the emerges bottom of the chute and continues sliding along a horizontal surface with ient of kinetic friction 0.267. How far from the bottom of the chute does the toy zebra come to rest? Takeg 9.81 m/s2 Number 901 There is a hint available! View the hint by clicking on the bottom divider Click on the divider bar again to hide the hint.

Explanation / Answer

energy lost = K.E.+ P.E/.= 1/2) mv2 +mgh

here m is the mass, v is the velocity, g is gravitational constant, h is height

putting the values we get

energy lost=1/2)m (1.57)2 +m(9,8)(1.01)=1.232m+9.9m =11.132m joule.......1)

now thw work done by the friction = ( coefficient of Kinetic friction)*m*g*d =0.267*m*9.81*d joule.......2)

we know energy lost= work done

so equating equation 1) and 2)

we get 11.132=2.62*d

d= 11.132/2.62=4.25m

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