A watermelon is thrown sideways from the rooftop edge of a 8.0 meter tall buildi

Question

A watermelon is thrown sideways from the rooftop edge of a 8.0 meter tall building, as shown in the diagram The melon is meant to land on a target on the ground that is 3.30 meters sideways from the building edge where the melon is launched? What will the watermelon's initial sideways velocity need to be A ball s thrown with initial velocity 18 meter/sec at an angle 35 degree above the horizontal from the roof edge of a 20 meter tall building. (a) What is the velocity of the ball 2.00 seconds after being thrown? (b) What time will the ball hit the ground? (c) What distance will the ball land from the building? (d) What is the maximum height of the ball above the ground? A heavy rock is launched from the ground with initial speed 43.0 m/s at a 32 degree angle toward a 20 meter tall wall which is 150.0 meters away from the starting point. At what height does the rock hit the wall? A ball is thrown from the roof edge of a 25 meter tall building with initial speed 12 m/s at an angle of 30 degree below horizontal. Find the time and distance the ball lands from the building. Practice Set This set of practice questions do not reed to be turned in, and they will not be graded. Solutions to these will be posted on Blackboard by Wednesday. Practice From Textbook Chapter 3:Problems # 26ab, 27abc, 36, 45 Further Practice A cannonball is launched at initial speed 50 meter/sec at an angle 45 degree toward a tall wall 240 meters away. How high will the cannonball be above the ground when it hits the wall? A ball is launched at 40 meter/sec at a 70 degree angle above the roof edge of a 10 meter tall building. (a) What is the maximum height of the ball above the ground? (b) At what time will the ball be 60 meters above its starting height and be moving upward? (c) What is the velocity of the ball as it reaches the ground? A ball is shot sideways from a high building with velocity 15 meter/sec. The ball is programmed to light up when its speed through the air is 30 meter/sec. Find the time and (x, y) location after launch when the ball first lights up.

Explanation / Answer

D7) time taken to fall is given by,

h = 0.5 gt^2

t = sqrt (2h/g) = sqrt (2*8/9.8)

= 1.28 s answer

Sidewway velocity = s/t = 3.3/1.28

= 2.58 m/s answer

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