Part A An electron moves in the magnetic field B = 0.530 i^T with a speed of 0.5

Question

Part A

An electron moves in the magnetic field B = 0.530 i^T with a speed of 0.500 ×107m/s in the directions shown in the figure. For each, what is magnetic force F on the electron? (Figure 1)

Express vector F in the form of Fx, Fy, Fz, where the x, y, and z components are separated by commas.

Express vector F in the form of Fx, Fy, Fz, where the x, y, and z components are separated by commas.

Part B

A 92.0 A current circulates around a 1.90-mm-diameter superconducting ring.

What is the on-axis magnetic field strength 4.20 cm from the ring?

What is the ring's magnetic dipole moment?

Explanation / Answer

F = q*v cross B

(a) F = -1.6e-19*(0.5e7(-j)) cross 0.530T(i)

F = -4.24*10^-13 (-k)

in the negative k direction

So,

F = 0,0, -4.24*10^-13

(b) F = -1.6e-19*0.5e7*(0.707(-j) + 0.707(k)) cross 0.530(i)

F = -5.99*10^-13 N

F = 0, -5.99*10^-13 N, -5.99*10^-13 N

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