.oooo T-Mobile 11:48 PM webassign net According to our records you have not yet
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.oooo T-Mobile 11:48 PM webassign net According to our records you have not yet redeemed an access code for this class or purchased access online. The grace period will end Tuesday, June 20 2017 at 12:00 AM CDT After that date you will no longer be able to see your WebAssign assignments or grades Get access now. The best leaper in the animal kingdom is the puma, which can jump to a height of 3.7 m when leaving the ground at an angle of 45. With what speed must the animal leave the ground to reach that height? m/s A jet airliner moving initially at 3.70 x 102 mi/h due east enters a region where the wind is blowing at 1.00 x 102 mih in a direction 30.5 north of east. (Let the x-direction be eastward and the y-direction be northward.) (a) Find the components of the velocity of the jet airliner relative to the air, (b) Find the components of the velocity of the air relative to Earth, (c) Write an equation analogous to v. for the velocities and (In the given equation, is the velocity of observer B relative t observer E. Object A travels with velocity v. relative to observer B, and velocity v, relative to observer E.) (d) What are the speed and direction of the aircraft relative to the ground? north of rant Need Help? I A miniature quadcopter is located at --2som and --27om at r-o and moves with an average velocity having components v...-120 ms and ,--2somv.Explanation / Answer
Question 7 )
Using the formula ,
Maximum height traveled (H)= u^2 sin^2 / 2g
Given H = 3.7 m ,angle( ) = 45 °
Substituting the values ,
3.7 = u^2 *sin(2*45°)/ 4*9.8 = u^2/4*9.8
u = 12.043 m/s
Therefore speed = 12.043 m/s
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