In the picture below, the two wires carry current i_1 and i_2, respectively, wit

Question

In the picture below, the two wires carry current i_1 and i_2, respectively, with positive current to the right. The charge q is positive and has velocity v to the right. If i_1 = 0 and i_2 is greater than zero then the force on q is south. If i_2 = - i_1 then the force on q equals zero. If i_1 = i_2, then the wires are attracted to each other. If i_1 is less than i_2, then the force on q is south.. If V = 0, then the force on q is zero. If i_1 = 0 and i_2 is greater than zero, then the force on q points out of the page. If i_2 = 0 and i_1 is greater than zero, then the magnetic field near charge q points out of the page.

Explanation / Answer

Solution:

A) force will be in Upward direction using left hand thumb rule.

B)True- Indivisual force by wires will cancel each other out.(check direction by fleming's left hand thumb rule)

C)True- same directional current carrying wires attract each other

D)True- Similar to part (A)

E)As we know, F = vBl

hence; if v=0 => F=0

(Magnetic field doesnt exert any force on a stationary charge)

F)False(use fleming's left hand thumb rule for the direction of force)

G)False(the magnetic field direction will be inside the page-Using right hand rule)

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