Below are a variety of scenarios involving masses attached to ropes, which are a

Question

Below are a variety of scenarios involving masses attached to ropes, which are attached in turn to walls or to other objects. Where indicated, label the magnitude of the tension T in that rope as equal to, less than, or greater than Mg (which is the weight of an object of mass M). The three scenarios at the top involve massless, frictionless pulleys. All ropes are massless and do not stretch. The mass m is equal to M/2.

Map 2a Sapling Learning macmillan learning Below are a variety of scenarios involving masses attached to ropes, which are attached in turn to walls or to other objects. Where indicated, label the magnitude of the tension Tin that rope as equal to, less than, or greater than Mg (which is the weight of an object of mass M). The three scenarios at the top involve massless, frictioniess pulleys. All ropes are massless and do not stretch. The mass mis equal to M2. T- Mg T Mg

Explanation / Answer

Taking the top left to be a) , then to its right b), then c) to the right and so on:

a)

Equating forces : T = Mg <----- answer

b)

Equating forces :

Mg - T = Ma

T - mg = ma

------------------

(M-m)*g = (M+m)*a

So, a = (M - m)*g/(M+m) = (M/2)*g/(3*M/2) = g/3

So, T = M(g - a) = M*(g - g/3) = 2Mg/3

So, T < Mg ---------- answer

c)

2Mg - T = 2M*a

T - Mg = Ma

So, Mg = 3Ma

So, a = g/3

So, T = M*(4g/3)

So, T > Mg <-------answer

d) bottom row left most

Mg = T <------ answer

e)

Mg = 2T

So, T = Mg/2

So, T < Mg <----- answer

f)

Top rope: (M+m)g = T

So, T > Mg

Bottom rope :

mg = T

So, T < Mg

f)

T*cos(theta) = Mg

So, T = Mg/cos(theta)

So, T > Mg <------ answer

Related Questions

Navigate

• Browse (All)
• Browse B
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.