When a resistor is connected across the terminals of an ac generator (116 V) tha

Question

When a resistor is connected across the terminals of an ac generator (116 V) that has a fixed frequency, there is a current of 0.637 A in the resistor. When an inductor is connected across the terminals of the same generator, there is a current of 0.365 A in the inductor. When both the resistor and the inductor are connected in series between the terminals of this generator, what is (a) the impedance of the series combination and (b) the phase angle between the current and the voltage of the generator? Note: The ac current and voltage are rms values and power is an average value unless indicated otherwise.

Explanation / Answer

As we know that

Remember Capacitors work like parallel branches and inductuctors act like resistors in series
With ac circuits you construct a triangle with impedance as
the hypotenuse and resistance r on the base and reactance x
on the altitude.
R=116/.637=182.10367ohms
Ri=116/.365=317.80821

z=sqrt(182.10367^2+317.80821^2)=366.28195 ohms

b. phase angle is 90 degrees between current and voltage

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