A drum (see the figure) has a radius of 0.40 m and a moment of inertia of 5.4 kg

Question

A drum (see the figure) has a radius of 0.40 m and a moment of inertia of 5.4 kgm2. The frictional torque of the drum axle is 3.0 Nm. A 39 m length of rope is wound around the rim. The drum is initially at rest. A constant force is applied to the free end of the rope until the rope is completely unwound and slips off. At that instant, the angular velocity of the drum is 18 rad/s. The drum then decelerates and comes to a halt. In this situation, the angular momentum of the drum at the instant the rope slips off the peg is closest to:

Explanation / Answer

According to the question provided we need to find the value of the angular momentum of the drum.

Angular momentum = I * w = 5.4 kgm2 * 18 rad/s = 97.2 kg m2/s ==============ANSWER) 2ND LAST OPTION

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