Select the mathematical relationship between velocity (v) and time (t) for a coi

Question

Select the mathematical relationship between velocity (v) and time (t) for a coin tossed up into the air after it leaves the thrower's hand at t = 0s with a velocity of +15.0m/s. Assume that the positive direction is upward and the acceleration of the coin is -9.8m/s^2. v = 15m/s + (9.8m/s^2)t The given information is not enough. v = -15m/s + (-9.8m/s^2)t v = d/t v = 15m/s - (9.8m/s^2)t A ball has mass 55.0kg. In the three boxes below give the: 1. weight of the ball 2. magnitude of the gravitational force acting on the ball 3. The force a spring scale would read if the ball were hanging from it. the numerical part of your answer and the Unit when you enter your answers. Consider two identical balls. One is hanging on a spring scale in the laboratory, and one is hanging on a spring scale 25 km above the surface of the Earth. Which ball weighs more? Which ball has a larger mass? The ball above the surface of the Earth weighs more and both have the same mass. Both balls weigh the same and have the same mass. The ball in the laboratory weighs more and both have the same mass. The ball in the laboratory weighs more and has the more mass. Can't tell.

Explanation / Answer

Solution:

6) When the initial velocity = vi

final velocity = vf and acceleration = g=-9.8 m/s^2

time = t

vf = vi +at

=> for the tossed coin , 0 = vi -gt

=> v =15-9.8 t

7) Mass of the ball = 55 kg

1) Weight of the ball = mg = (55)(9.8) = 539 N

2) The gravitational force acting on the box = weight of the box = mg = 539 N .

3) When the same mass is vertically hanged from a spring , force = mg = 539 N .

All these three forces are equal since gravity acts on the box.

8) The balls have thesame mass .Mass is Changeless.

Weight on the surface of theearth is more .

Gravity decreases with altitude.

So weight of object on earth is Greater than that at the 25km height.

The ball in the Laborartory weighs more and Both have Same mass.

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