Two wave pulses travel on a string. Wave pulse A displaces the string by +3 cm a

Question

Two wave pulses travel on a string. Wave pulse A displaces the string by +3 cm at x = 8 m. Wave pulse B displaces the string by +2 cm at x = 8 m. If both reach x = 8 m at the same time, how much is the string displaced? +5 cm +6 cm +1 cm +16 m A fixed length of string has standing waves. How many wavelengths of the standing wave would fit into the length of string for the fourth mode (n = 4)? Two and a half Three and a half Three Two Four A sinusoidal wave traveling on a string is described by the equation y(x, t) = (3 cm) * sin ((2.85 mA-1) * x - (4.6 s^-1) * t). What is the wavelength of this wave? 3 cm 2.2 m 0.35 m 2.85 m

Explanation / Answer

1. A = A1 + A2 = 2 + 3 = 5 cm

2. for 1st mode, half wavelength

2nd -> 1 wavelength

3rd -? one and half

4th -> two

Ans: Two

3. y = 3 cm sin(2.85x - 4.6t)

general equation: y = A sin(kx - wt)

and k = 2 pi / lambda

2.85 = 2 pi / lambda

lambda = 2.2 m

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.