core: 0 of 1 pt 3of8(8 complete) HW Score: 78.13%, 6.25 of 8 p Review 8-49 (algo

Question

core: 0 of 1 pt 3of8(8 complete) HW Score: 78.13%, 6.25 of 8 p Review 8-49 (algorithmic) Question Help A robotic rover on Mars finds a spherical rock with a diameter of 10 centimeters. The rower joules. Gravitational acceleration on Mars is 3.7 meters per second squared. What is the specific gravity of the rock? r picks up the rock and ifts t 25 centimeters straight up. The resuling potentisl energy of the rock relative to the surtace is 2 Click ion to view the nversion table. Click the icon to view density of water The specific gravity of the rock is 14Round your answer to two signiticant digts.) Entor your answer in the answer box and then click Check Answer Clear All Final Checlk F3 888 F4 2 3 4 8

Explanation / Answer

Diameter of rock, d=10 cm

Radius of rock, r= d/2 = 5 cm= 5*10^-2 m

Gravitational Potential energy, U=2 J

As gravitational potential energy of mass m when picked up to a height h is

                U=mgh = (r V)gh = (r (4r^3)/3) gh

                r =3U/(4r^3)gh = 3*2/(4*3.14*(5*10^-2)^3 *3.7*25*10^-2) = 4131.52 kg/m^3

As density of water =1000 kg/m^3

So

Specific gravity of the rock is= density of rock / density of water = 4131.52/1000 =4.13152

On rounding off

Specific gravity of the rock is= 4.13

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