du 3G 5:03 AM @ 35% ID + HW2 summer 2017 Halliday, Fundamentals of Physies, 10e
ID: 1629486 • Letter: D
Question
du 3G 5:03 AM @ 35% ID + HW2 summer 2017 Halliday, Fundamentals of Physies, 10e Chapter 24, Problem 009 An infinite, nonconducting sheet has a surface charge density +6.61 pC/m2. (a) How much work is done by the electric field due to the sheet if a particle of charge q= 4.81 x 10-19 C is moved from the sheet to a point P at distance d = 3.69 cm from the sheet? (b) If the electric potential V is defined to be zero on the sheet, what is V at P? ) Number (b) Number Click if you would like to Show Work for this question: Open Show Work Question Attempts: 0 of 1 used Savi NR '" Coonge © 2000-2017 by John Wiey & Sons, Inc or reated conori" Al reserExplanation / Answer
A.
Work done is given by:
W = F*d = q*E*d
Electric filed is given by:
E = sigma/2*e0
W = q*sigma*d/(2*e0)
given that:
sigma = 6.61*10^-12 C/m^2
e0 = 8.85*10^-12
q = 4.81*10^-19 C
d = 3.69 cm = 0.0369 m
Using these values:
W = 4.81*10^-19*6.61*10^-12*0.0369/(2*8.85*10^-12)
W = 6.63*10^-21 J
B.
W = -q*dV
dV = -W/q = -6.63*10^-21/(4.81*10^-19)
dV = -0.0137
given that V = 0 at the surface of sheet, So
Vp - 0 = -0.0137 V
Vp = -0.0137 V
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