Umbrella ,% Chapter 16(207) × ALarge Capacitance Of/XYe Find The Follow ng anTxV

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Umbrella ,% Chapter 16(207) × ALarge Capacitance Of/XYe Find The Follow ng anTxVGpd : www.webassign.net/web/Student/Assignment Responses submit?dep.16244082 Submit Answer Save Progress Practice Another Version -45 points SerCP11 16 P041 For the system of capacitors shown in the figure below, find the following. (Let C1 9.00 F and C2-6.00 F.) C 6.00 AF 6.00F 2.00 uF C 90.0 V (a) the equivalent capacitance of the system N (b) the charge on each capacitor on C1 on C2 on the 6.00 F capacitor on the 2.00 F capacitor AC uC (c) the potential difference across each capacitor across C across C2 across the 6.00 HF capacitor across the 2.00 F capacitor Need Help? aan 1 1. 15/15 points Prenous Answers SerCP11 16 P051

Explanation / Answer

A.

Remember:

For parallel combination

Ceq = C1 + C2 + C3 +...............

for series combination

1/Ceq = 1/C1 + 1/C2 + 1/C3 + ............

for 2 capacitors in series it will be

Ceq = C1*C2/(C1+C2)

Using this Information:

6 uF and 2 uF are in series, So

Cs1 = 6*2/8 = 1.5 uF

9 uF and 6 uF are in series, So

Cs2 = 9*6/15 = 18/5 = 3.6 uF

Now 1.5 uF and 3.6 uF are in parallel, So

Ceq = 1.5 + 3.6 = 5.1 uF

B.

Qeq = Ceq*Veq

Qeq = 5.1 uF*90 = 459 uC

Now remember in capacitors parallel combination voltage distribution in each part will be same and in series combination charge distribution in each capacitor will be same.

Vs1 = Vs2 = Veq = 90 V

Qs1 = Cs1*Vs1 = 1.5 uF*90 = 135 uC

Charge on 2uF = 135 uC, Voltage on 2uF = 135/2 = 67.5 V

Charge on C2 = 135 uC, Voltage in C2 = 135/6 = 22.5 V

Qs2 = Cs2*Vs2 = 3.6 uF*90 = 324 uC

Charge on 6uF = 324 uC, Voltage on 6uF = 324/6 = 54 V

Charge on C1 = 324 uC, Voltage in C1 = 324/9 = 36 V

Let me know if you have any doubt.

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