a 940 kg car slides on ice into the rear of a a 2460 kg truck that was at rest t

Question

a 940 kg car slides on ice into the rear of a a 2460 kg truck that was at rest the pre collision speed of the car was 12.5 m/s. determine the post collision speed of the two entangled vehicles as they slide across the ice ? a 940 kg car slides on ice into the rear of a a 2460 kg truck that was at rest the pre collision speed of the car was 12.5 m/s. determine the post collision speed of the two entangled vehicles as they slide across the ice ? a 940 kg car slides on ice into the rear of a a 2460 kg truck that was at rest the pre collision speed of the car was 12.5 m/s. determine the post collision speed of the two entangled vehicles as they slide across the ice ?

Explanation / Answer

Given,

Mass of car, m1 = 940 kg

Mass of truck, m2 = 2460 kg

Initial velocity of car, v1 = 12.5 m/s

Let us assume that v be the velocity of entangled vehicles, then

Applying law of conservation of momentum,

Momentum before collision, Pi = Momentum after collision, Pf

(m1 x v1) + (m2 x v2) = (m1 + m2) x v

(940 x 12.5) + 0 = (940 + 2460) x v

v = 3.456 m/s

So, the speed of two entangled vehicles will be 3.456 m/s.

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