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p?attempt 344459 WIT DTS!! wiT Email OwiT Library institute WIT DTS WIT Email WIT Libr Welcome to BHCConline and to the Moodle Learning Management System! .252-BD1 magnetic fields eoc 6-magnetic fields Question 1An anti-proton, which has the same properties as a proton but negative charge, is moving the combined Not complete Points out of 2.00 500 m/s E-1000 V/m What is the acceleration of the anti-proton at this instant? Give the direction as positive if it is up or negative if it is down BHCC Home I Site Map | Free Tutoring I Office Hours Contact Us 2015 Bunker Ha community College, All Rights Reserved 02129-2925 | Telephone: 617 2282000 I TTY 617 228 2051 Bunker Hill

Explanation / Answer

Using newton's law:

Fnet = Fm + Fe

m*a = q*VxB + q*E

a = q*(VxB + E)/m

VxB is point downward and electric field is point upward, So

Using given values:

a = (-1.6*10^-19)*(-500*2.5 + 1000)/(1.67*10^-27)

a = 2.395*10^10 m/sec^2

Let me know if you have any doubts.

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