A tiny sphere of mass 8.30 mg and charge -2.80 nC is initially at a distance of

Question

A tiny sphere of mass 8.30 mg and charge -2.80 nC is initially at a distance of 1.64 mu m from a fixed charge of +8.69 nC. (a) If the 8.30-mg sphere is released from rest, find its kinetic energy when it is 0.500 mu m from the fixed charge. 335 Your response differs from the correct answer by more than 10%. Double check your calculations. J (b) If the 8.3C-mg sphere is released from rest, find its speed when it is 0.500/mu m from the fixed charge. 286 is within 10% of the correct value. This may be due to roundoff error, or you could have a mistake in your The figure below is a graph of an electric potential as a function of position. If a positively charged particle Is placed at point A, go to the left remain at point A oscillate around point 8 go to the right

Explanation / Answer

m, mass= 8.30 mg

q1 = ist charge = -2.80nC

q2 = second charge = 8.69 nC

r= distance between the two charges = 1.64 um

displacement ,d = 0.500 um

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1) Work done = change in kinetic energy

Force *displacement = K.E_final- K.E_initial

[K.E_initial = 0 ( initially at trest]

K.E_final = Force *displacement

= ( k*q1*q2/ r2)*d

= (9*109*2.80*10-9*8.69*10-9 / (1.64*10-6)2) *0.500*10-6

= 0.0407 J

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2) K.E = (1/2)*m*V2

V2 = 2*K.E / m

V = (2*K.E / m)1/2

V( Velocity) = ( 2*0.0407 / 8.30*10-6 kg)1/2

V= 99.03 m/s

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