(a) Determine the direction of the electric field. Answer: up or down . (b) Dete
ID: 1631686 • Letter: #
Question
(a) Determine the direction of the electric field.
Answer: up or down.
(b) Determine the charge on the bead.
A positively charged bead having a mass of 1.00 g falls from rest in a vacuum from a height of 3.50 m in a uniform vertical electric field with a magnitude of The bead hits the ground at a speed of 22.0 m/s.
(a) Determine the direction of the electric field.
Answer: up or down.
(b) Determine the charge on the bead.
Round your answer to three significant figures. Take the acceleration of gravity to be
_____
3.00 × 10 " N/CExplanation / Answer
Given that
mass m=1 g
electric field E=3*10^4 N/c
speed V=22 m/s
height h=3.5 m
basing on the concept of the intensity of electric field
now we find the charge on the bead
v^2-u^2=2qEh/m
22^2-0^2=2*q*3*10^4*3.5/10^-3
0.484=21*10^4 *q
charge q=2.305*10^-6 C
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