Three resistors connected in parallel have individual voltages labeled Delta V_1

Question

Three resistors connected in parallel have individual voltages labeled Delta V_1, Delta V_2 and Delta V_3, respectively. Which of the following expresses the value of the total voltage Delta V_T taken over the three resistors together? a. Delta V_T = Delta V_1 + DeltaV_2 + Delta V_3 b. Delta V_T = (1/Delta V_1 + 1/Delta V_2 + 1/Delta V_3) c. Delta V_T = DeltaV_1 = Delta V_2 = Delta V_3 d. Delta V_ T = (1/Delta V_1 + 1/Delta V_2 + 1/Delta V_3)^-1 Three resistors connected in series each carry currents labeled I_1, I_2 and I_3. Which of the following expresses the value of the total current I_T in the system made up of the three resistors in series? a. I_T = I_1 = I_2 = I_3 b. I_T = I_1 + I_2 + I_3 d. I_T = (1/I_1 +1/I_2 + 1/I_3) ^- 1 Three capacitors connected in series have individual voltages labeled Delta V_1, Delta V_2 and Delta V_3, respectively. Which of the following expresses the value of the total voltage Delta V_T taken over the three resistors together? a. Delta V _T = Delta V_1 + Delta V_2 + Delta V_3 b. Delta T = (1/Delta V_1 + 1/Delta V_2 + 1/Delta V_3) c. Delta V_T = Delta V_1 = Delta V_2 = Delta V_3 d. Delta V_T = (1/Delta V_1 + 1/Delta V_2 + 1/Delta V_3)^-1 Three capacitors connected in parallel each carry have a charge labeled Q_1, Q_2 and Q_3. Which of the following expresses the value of the total current I_T in the system made up of the three resistors in series? a. Q_T = Q_1 = Q_2 = Q_3 b. Q_T = Q_1 + Q_2 + Q_3 c. Q_T = (1/Q_1 + 1/Q_2 + 1/Q_3) d. Q_T = (1/Q_1 + 1/Q_2 + 1/Q_3)^-1

Explanation / Answer

a) Resistors connected in parallel have same potential difference across them. So answer is c)

b)Resistors connected in series have same current flowing through each of them. So answer is a)

c)Sum total of voltage drop across each capacitor will give the total potential difference. So answer is a)

d)Total charge will be equal to the sum of individual charges across each capacitor. So answer is b)

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