3\" (6 points) A rectangular coil with 5 turns of width = 0.300 cm and length =

Question

3" (6 points) A rectangular coil with 5 turns of width = 0.300 cm and length = 0.500 cm has a total resistance of 5 It moves with velocity 3.12 m/s into a uniform magnetic field of 54.6 mT as shown. (a) what is the magnitude and direction of the current induced in the loop as it enters the B field. (b) What is the force on the loop (magnitude and direction) as it enters the field. (c) What is the force on the loop while it is completely within the B field? (d) What is the direction of the induced current as it leaves the field? to xXxXxXx xXXxXxx

Explanation / Answer

A) Induced emf V = BvwN= 0.0546*3.12*0.003*5

= 0.000511*5 N

Current = V/R = 0.000511*5/5

= 0.000511 A answer

Counterclockwise by lenz law.

B) F = BiwN = 0.0546*0.000511*0.003*5 = 4.185*10^-7 N

C) Fnet = 0 as forces on all four sides will cancel out.

D) clockwise, by lenz law it will be in direction will create a field in existing direction of the field.

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