The paper dielectric in a paper-and-foil capacitor is 7.75×102 mm thick. Its die

Question

The paper dielectric in a paper-and-foil capacitor is 7.75×102 mm thick. Its dielectric constant is 2.50, and its dielectric strength is 48.5 MV/m . Assume that the geometry is that of a parallel-plate capacitor, with the metal foil serving as the plates.

Part A) What area of each plate is required for a 0.160 F capacitor? (m^2)

If the electric field in the paper is not to exceed one-half the dielectric strength, what is the maximum potential difference that can be applied across the capacitor? (V)

Explanation / Answer

1.

We know that

V = E*d

V = 48.5*10^6*7.75*10^-5 = 3758.75 V

Capacitance is given by:

C = k*e0*A/d

d = 7.75*10^-5 m

e0 = 8.85*10^-12

k = 2.5

A = C*d/(k*e0)

A = 0.16*10^-6*7.75*10^-5/(2.5*8.85*10^-12)

A = 0.56 m^2

2.

given that

E = Emax/2 = 48.5/2 = 24.25 MV/m

V = E*d

V = 24.25*10^6*7.75*10^-5 = 1879.38 V

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