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Below is solution for problem i need solution of lab given below on the basis of

ID: 1632089 • Letter: B

Question

Below is solution for problem i need solution of lab given below on the basis of the following problem. please help. no need to post solution of given problem i know its solution already, Just help me to solve lab report from section 3.1 to end ...thanks

You have a 200 grams cart that is attached to a string. At the other end of the string a 17 gram weight is attached. The image below shows the set up (and a lots of hints).

3.3.1  Calculate the force due to gravity upon the weight Fw = 0.166 N

3.3.2 Calculate the total mass of the system Mt = 0.217 Kg

3.3.3 Calculate the acceleration of the cart a = 0.764 m/s^2

Solve the below experiment please . Don't go in more details. Be to the point. I need it to be done asap.

Experiment:

3.1

   Mass of the cart:       Mass of the weight:

   Initial Position of the cart:    Final Position of the cart:

   Computed acceleration:

Create an entry below to show your work. Use the "Mathematical Equation" entry or upload an "Attachment" with a picture of your handwriting.

Compare the values of acceleration that you have:

Theoretical Acceleration (from 3.1) a1=

Experimental Acceleration from the position vs time graph (from 3.3.3). a2 =

Experimental Acceleration from the velocity vs time graph (from 3.5). a3 =

3.2

Run your experiment.

You will need to get a nice position vs time graph in Capstone.

In order to calculate your experimental acceleration, please record the following data points in the table below.

   mA & mB should be shortly after the cart begins accelerating

mC & mD should be shortly before the cart stops accelerating

Compute your experimental initial and final velocities. Use the position time graph, and the data points you collected.

Record your velocities in the table below:

Initial velocity (Vi) will be the average velocity in the interval between the mA to mB data points

Final velocity (Vf) will be the average velocity in the interval between the mC to mD data points

Time

Velocity

3.3.2  Compute the total change in velocity and the total change in time

   Change in time :

Change in velocity:

3.3.3  Compute your experimental acceleration (value from physical measurements)

   Acceleration:

3.4

If you erased your data: run your experiment again, get a nice position vs time graph.

Use Capstone to display a Velocity Time graph using the same data.

Record the following data points on the table below (this will be used to calculate experimental acceleration):

   v1 should be shortly after the cart begins accelerating (similar to the interval of points mA & mB from 3.2)

v2 should be shortly before the cart stops accelerating (similar to the interval of points mC & mD from 3.2)

In the entry below sketch your Capstone graph.

Don't forget to:

   Label your axes

   Label all your points clearly

3.5

Compute your experimental acceleration from the data in 3.4 (value from physical measurements)

   Experimental Acceleration:

3.6

  If you erased your data: run your experiment again, get a nice position vs time graph.

Use Capstone to display an Acceleration Time graph using the same data.

Record the following data points on the table below (this will be used to calculate experimental acceleration):

   a1 should be shortly after the cart begins accelerating (similar to point mA point from 3.2)

a5 should be shortly before the cart stops accelerating (similar to point mD point from 3.2)

a2, a3 and a4 should be between a1 and a5 and "evenly" spaced within the time interval

Compute the average of all accelerations.

   Experimental Acceleration :

      3.7.2 Compute the percent errors of your Experimental accelerations (a2, a3)

% Error = | (Theoretical value - Experimental value) / Theoretical value | * 100

Position Key Points Point Time Position mA mB mC mD
What we know: Mass of Cart: mc (1) Solve for (accelerating) Mass of force due to gravity upon. Acceleration of gravity:g Weight: mw weight Fw Key relationship F=ma (2) observe that C and W move together. Acceleration a is equivalent: . W: in negative Y direction (3) Solve for acceleration due to Fw C: in negative X direction .a in negative direction (for both)

Explanation / Answer

3.3.1

the force due to gravity upon the weight Fw = 0.017 X 9.8

= 0.166 N

3.3.2

the total mass of the system Mt = 200 + 17

= 217 grams

= 217 / 1000

= 0.217 Kg

3.3.3

the acceleration of the cart a = 0.166 / 0.217

= 0.764 m/s2

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