An aluminum calorimeter with a mass of 100 g contains 229.0 g of water. The calo

Question

An aluminum calorimeter with a mass of 100 g contains 229.0 g of water. The calorimeter and water are in thermal equilibrium at 20.0°C. An iron block with an initial temperature of 115°C is placed into the water. The entire system stabilizes at a final temperature of 28.9°C. Determine the mass of the iron block in grams. Assume that no heat is transferred to or from the surroundings.

_____g

Question 2

How many grams of coffee must evaporate from 650 g of coffee in a 160 g glass cup to cool the coffee from 95.0°C to 49.0°C? You may assume the coffee has the same thermal properties as water and that the average heat of vaporization is 2340 kJ/kg (560 cal/g). (You may neglect the change in mass of the coffee as it cools, which will give you an answer that is slightly larger than correct.)

____g

Question 3

You pour 150 g hot coffee at 78.7°C and some cold cream at 7.50°C to a 115-g cup that is initially at a temperature of 22.0°C. The cup, coffee, and cream reach an equilibrium temperature of 61.0°C. The material of the cup has a specific heat of 2528 J/(kg · °C) and the specific heat of both the coffee and cream is 4186 J/(kg · C). If no heat is lost to the surroundings or gained from the surroundings, how much cream did you add?
_____g

PLEASE ANSWER ALL THE QUESTIONS DONT GIVE ANY WRONG ANSWERS THANKS FOR YOUR HELP

Explanation / Answer

here,

mass of water , m1 = 100 g

mass of alumunium , m2 = 229 g

let the mass of iron block be m3

heat lost by iron = heat gained by ( alumunium + water )

m3 * Ci * ( 115 - 28.9) = m1 * Cw * ( 28.9 - 20) + m2 * Ca * ( 28.9 - 20)

m3 * 0.45 * ( 115 - 28.9) = 100 * 4.186 * ( 28.9 - 20) + 229 * 0.9 * ( 28.9 - 20)

solving for m3

m3 = 143.5 g

the mass of iron is 143.5 g

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