Find the net electric force that the two charges would exert on an A -3.00 nC po
ID: 1632714 • Letter: F
Question
Find the net electric force that the two charges would exert on an
A -3.00 nC point charge is at the origin, and a second -6.00 nC point charge is on the x-axis at x = 0.800 m. Find the net electric force that the two charges would exert on an electron placed at point on the x-axis at x = 0.200 m. Express your answer with the appropriate units. Enter positive value if the force is in the positive x-direction and negative value if the force is in the negative x-direction. F_x = 8.39 times 10^-17 N Find the net electric force that the two charges would exert on an electron placed at point on the x-axis at x = 1.20 m. Express your answer with the appropriate units. Enter positive value if the force is in the positive x-direction and negative value if the force is in the negative x-direction. F_x = ______ ________ Find the net electric force that the two charges would exert on an electron placed at point on the x-axis at x = -0.200 m. Express your answer with the appropriate units. Enter positive value if the force is in the positive x-direction and negative value if the force is in the negative x-direction. F_x = _________ _______Explanation / Answer
The third charge is electron and other two are negative charges . so, force b/w them will be repulsive.
(d)
at x = 0.2 m,
The electron is placed b/w both the charges.
F2<------- (e) ------->F1
Net electric force = [k*q1*e / r1^2] - [k*q2*e / r2^2]
F = 9*10^9*1.6*10^(-19)*10^(-9) * [ 3/(0.2)^2 - 6/(0.6)^2]
F = 8.4*10^(-17) N (along +x axis)
(e)
at x = 1.2 m
The electron is localed at right side of -6 nC charge. Force on electron due to both charges will be +x direction.
q1 q2 (e)------>F1------->F2
Net electrc force F = [k*q1*e / r1^2] + [k*q2*e / r2^2]
F = 9*10^9*1.6*10^(-19)*10^(-9) * [ 3/(1.2)^2 + 6/(1.2 - 0.8)^2]
F = 5.7*10^(-17) N (along +x axis)
(f)
at x = -0.2 m
The electron is placed at left side of -3nC charge.
. Force on electron due to both charges will be in same direction (-x direction).
F1<--------F2<--------(e) q1 q2
F = -[k*q1*e / r1^2] - [k*q2*e / r2^2]
F = -9*10^9*1.6*10^(-19)*10^(-9) * [ 3/(0.2)^2 + 6/(0.2 + 0.8)^2]
F = -11.66*10^(-17) N (along -x axis)
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