you can see the incorrect answer I already got using the equation R*m*g*sin(thet
ID: 1633172 • Letter: Y
Question
you can see the incorrect answer I already got using the equation R*m*g*sin(theta)/B^2*l^2*cos(theta)
The figure below shows a bar of mass m = 0.300 kg that can slide without friction on a pair of rails separated by a distance l = 1.20 m and located on an inclined plane that makes an angle theta = 32.0 degree with respect to the round. The resistance of the resistor is R = 1.50 Ohm and a uniform magnetic field of magnitude B = 0.500 T is directed downward, perpendicular to the ground, over the entire region through which the bar moves. With what constant speed v does the bar slide along the rails?Explanation / Answer
Component of B perpendicular to the plane
= Bcos32°
=> emf induced in the coil
= Bcos32° * 1.2 * v =
=> current in the bar,
I = /R = (v/R) * 1.2 Bcos32°
Force opposing the downward motion
F = I * L * Bcos32° = (v/R) * (1.2 Bcos32°)2
As the bar starts sliding, v keeps on increasing and so does F till F balances the downward component of the weight of the bar
=> mgsin32° = (v/R) * (1.2 Bcos32°)2
=> velocity, v
= (mgRsin32°) / (1.2 Bcos32°)2
= (0.3 * 9.81 * 1.5 * sin32°) / (1.2 * 0.5 * cos32°)2
= 9.03 m/s.
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