A square coil of wire side I = 5.00 cm contains 100 loops and is positioned perp

Question

A square coil of wire side I = 5.00 cm contains 100 loops and is positioned perpendicular to a uniform 0.600-T magnetic field, as shown in Fig 2. It is quickly pulled from the field at constant speed (moving perpendicular to B^vector) to a region where B drops abruptly to zero. At t = 0, the right edge of the coil is at the edge of the field. It takes 0.100 s for the whole coil to reach the field-free region. The coil total resistance is 100 Ohm. Find (a) the rate of change in flux through the coil. (b) The emf and current induced. (c) How much energy is dissipated in the coil (d) What was the average force required?

Explanation / Answer

(A) Magnetic flux = N B A

= (100) (0.60) (0.05^2)

= 0.0375 Wb

rate of change of flux = (0.0375) / 0.100

= 0.375 Wb/s

(B) induced emf = rate of change of magnetic flux

= 0.375 Volt

current, I = e / R = 0.375 / 100

= 3.75 x 10^-3 A

(C) P = I^2 R

= (3.75 x 10^-3)^2 (100)

= 1.41 x 10^-3 W

(d) v = 0.05 / 0.10 = 0.5 m/s

P = F.v

1.4 x 10^-3 = 0.5 F

F = 2.81 x 10^-3 N

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.