One mole of an ideal monatomic gas at an initial volume V_1 = 10 L follows the c

Question

One mole of an ideal monatomic gas at an initial volume V_1 = 10 L follows the cycle shown in the figure. All the processes are quasi-static. (a) Find the temperature of each state of the cycle. 120.27 K (state 1) 240.55 K (state 2) 240.55 K (state 3) (b) Find the heat absorbed by the gas for each part of the cycle. (Use a negative if heat is removed from the gas.) 1.50 kJ (1 to 2) 1.386 kJ (2 to 3) -2.5 kJ (3 to 1) (c) Find the efficiency of the cycle. 27.85 % Use the ideal-gas law to find the temperatures of each state of the gas and the heat capacities at constant volume and constant pressure to find the heat absorbed by the gas for the constant-volume and isobaric processes. Because the change in internal energy is zero for the isothermal process, you can use the expression for the work done on or by a gas during an isothermal process to find the heat flow during such a process. Finally, find the efficiency of the cycle from its definition.

Explanation / Answer

c] total work done by gas = 1.5+1.386-2.5 = 0.386 kJ = 386 J

total heat given = 1.5+1.386 = 2.886 kJ

efficiency = 0.386*100/2.886

= 13.37% answer

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