Linearly polarized light with an intensity of 4.10 W/m2 passes through a polariz

Question

Linearly polarized light with an intensity of 4.10 W/m2 passes through a polarizer whose transmission axis is tilted at an angle of e - 51.0 clockwise relative to the vertical. The polarization angle, , for the incoming light is 20.4. Linearly Polarized: Light What is the intensity of the light once it has passed through the polarizer? 3.43 wm2 Tries 3/10 Previous Tries Submit Answer What is the angle of polarization of the light once it has passed through the polarizer? Measure the angle relative to the vertical. (Use deg for degrees.) 31.0 deg

Explanation / Answer

when an polarised light is passed through a polarizer, its intensity becomes half.

hence I1 = Io/2 = 4.10/2 = 2.05

51° clockwise

I1 = intensity of light after passing the polarizer = Io Cos2(51 - 20.4) = 4.10 x Cos2(30.6)= 3.037

To calculate cos2theta, first calculate cos theta and then square it. Or in case of equation, simply square the (costheta).

I hope it helps!

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