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session.masteringphysics.com Course Home Course Home Chegg Study | Guided Solutions and Study H MasteringPhysics: Chapter 20 ) Jacquees YoExcuse Me Miss) Chanter 20 Problem 20.15 a previous 3 of 11 next Problem 20.15 u= 5.8x105 Submit My Answers Give Up A helium ion (Q +2e) whose mass is 6.6× 10-27 kg is accelerated by a voltage of 3500 V . Correct Part B What will be its radius of curvature if it moves in a plane perpendicular to a uniform 0.370 T field? Express your answer to two significant figures and include the appropriate units. cm Submit My Answers Give Up Incorrect; Try Again; 5 attempts remaining Part C What is its period of revolution? Express your answer to two significant figures and include the appropriate units. T-0.39 S Submit My Answers Give Up Incorrect Try Again; 3 attempts remaining ContinueExplanation / Answer
(A) Gain in KE = q deltaV
m v^2 / 2 = q deltaV
(6.6 x 10^-27) v^2 / 2 = (2 x 1.6 x 10^-19) (3500)
v = 5.8 x 10^5 m/s
(B) while in magnetic field,
magnetic force = centrpetal force
q v B = m v^2 / r
r = m v / q B
r = (6.6 x 10^-27)(5.83 x 10^5) / (2 x 1.6 x 10^-19 x 0.370)
r = 0.032 m = 3.2 cm
(C) T = 2pi r / v
T = 3.5 x 10^-7 sec
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