2.3 Determine the magnitude of the resultant force Fr = F1 + F2 assume that F1=2
ID: 1635976 • Letter: 2
Question
2.3 Determine the magnitude of the resultant force Fr = F1 + F2 assume that F1=260lb and F2=385lb Can some one break down the interior angles of this I'm trying to use addition by parallelogram then using law of cosines. Thank you previous 1 2 of 9 next Part A e FR = Fi + F2 . Assume that F-260 lb and F,=385 lb Express your answer to three significant figures and include the appropriate units. Fi FR Value Units Submit My Answers Give Up rt B Determine the direction of the resultant force FR. measured counterclockwise from the positive a axisExplanation / Answer
to find the resultant of the given two forces, we can write the forces in vector notation
let the upward direction be +y axis and the right direction be +x axis
then
we can write, in component form
F1 = F1cos(30)j + F1sin(30)i [ where i is unit vector along x axis and j is unit vector along y axis)
similiarly
F2 = F2[cos(45)i + sin(45)j]
so net force is given by
F = F1 + F2 = (F1sin(30) + F2cos(45))i + (F1cos(30) + F2sin(45))j
now, F1 = 260 lb
F2 = 385 lb
so, F = 397.2361i + 497.4027 j
so magnitude of F is |F| = sqroot(397.2361^2 + 497.4027^2) = 636.557 lbs
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