=I\'m not sure what I\'m doing wrong for part B of the question below! A step by

Question

=I'm not sure what I'm doing wrong for part B of the question below! A step by step of how you arrived at the answer would be really helpful!

Multiple Concept Example 9 provides background pertinent to this problem. The magnitudes of the four displacement vectors shown in the drawing are A = 14.0 m, B = 10.0 m, C = 12.0 m, and D = 26.0 m.

Determine the (a) magnitude and (b) direction for the resultant that occurs when these vectors are added together. Specify the direction as a positive (counterclockwise) angle from the +x axis.

My calculations...

Ax= -13.16, Ay= 4.79, Bx= 0, By= 10, Cx= -9.83, Cy = -6.88, Dx= 16.71 Dy= -19.92

Explanation / Answer

In the question no drawing shown or any kind of link for the drawing.

I'll gonna explain the answer in general so that you can solve any problem of this kind.

SOLUTION:

Break down the resultant into its x- and y-components, using trigonometry to add the vectors:

R_x = Acos(a) + Bcos(b) + Ccos(c) + Dcos(d)
R_y = Asin(a) + Bsin(b) + Csin(c) + Dsin(d)

where
R_x = x-component of the resultant
R_y = y-component of the resultant
A, B, C, D = magnitudes of vectors A, B, C, D
a, b, c, d = angle each vector makes with the horizontal axis

Now you can find the magnitude and direction of the resultant:

R = [(R_x)² + (R_y)²]
= tan^-1(R_y/R/x)

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