In the practice of standing waves of a vibrating string, 200g is the suspended m

Question

In the practice of standing waves of a vibrating string, 200g is the suspended mass causing a tension in the wire and the wave originated by the mechanical vibrator travels through it. Calculate the propagation speed of the wave, if the wire has a linear density of 0.00295g / cm. A. 8165.27 cm / s B. 8192.50 cm / s C. 8155.27 cm / s D. 8145.27 cm / s In the practice of standing waves of a vibrating string, 200g is the suspended mass causing a tension in the wire and the wave originated by the mechanical vibrator travels through it. Calculate the propagation speed of the wave, if the wire has a linear density of 0.00295g / cm. A. 8165.27 cm / s B. 8192.50 cm / s C. 8155.27 cm / s D. 8145.27 cm / s In the practice of standing waves of a vibrating string, 200g is the suspended mass causing a tension in the wire and the wave originated by the mechanical vibrator travels through it. Calculate the propagation speed of the wave, if the wire has a linear density of 0.00295g / cm. A. 8165.27 cm / s B. 8192.50 cm / s C. 8155.27 cm / s D. 8145.27 cm / s

Explanation / Answer

Where T = tension = weight suspended = M*g = 200*981 = 196200 dyne

And m = linear mass density = 0.00295g / cm.

Hence

v = (T/m)1/2 = (196200/0.00295)1/2 = 8155.2728cm/s

So the option – c is correct.

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