Need to solve for specific heat of steel. Need help with specific heat of steel

Question

Need to solve for specific heat of steel.

Need help with specific heat of steel calculations.

My data recorded is as follows:

initial object temp= 28.6

initial water temp=28.4

initial bolt (object) mass =21.0

initial water mass= 150g

final water temp=30.9

change in water temp=2.5

I need the

1) the specific heat of steel based on my data

2))Since the specific heat of steel is listed as 490J/kg Celsius, find the percent error for my calculations of specific heat relative to the value listed

Please show work so I know how to do it in the future. Thanks!

Explanation / Answer

In this we assume that heat lossed by metal is equal to heat gained by the object

ie

qsteel = qwater

(mass)s (t)s (Cp)s = (mass) (t) (Cp)

here

(mass)s = 21g

Change in water temperature = 2.5oC

Change in object temperature = 30.9 - 28.6 = 2.3oC

Cp = 4.187 Jg-1oC-1

hence we got

21 x 2.3 x (cp)s = 150 x 2.5 x 4.187

(Cp)s = 32.5 J/goC

Related Questions

Navigate

• Browse (All)
• Browse N
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.