Circular Motion Ranking Task Six artificial satellites circle a space station at

Question

Circular Motion Ranking Task

Six artificial satellites circle a space station at constant speed. The mass m of each satellite, distance L from the space station, and the speed v of each satellite are listed below. The satellites fire rockets that provide the force needed to maintain a circular orbit around the space station. The gravitational force is negligible.

Rank each satellite based on its acceleration.

Rank from largest to smallest. To rank items as equivalent, overlap them.

Help

Reset

m=200kg
L=5000m
v=160m/s

m=100kg
L=2500m
v=160m/s

m=400kg
L=2500m
v=80m/s

m=800kg
L=10000m
v=40m/s

m=200kg
L=5000m
v=120m/s

m=300kg
L=10000m
v=80m/s

Help

Reset

m=200kg
L=5000m
v=160m/s

m=100kg
L=2500m
v=160m/s

m=400kg
L=2500m
v=80m/s

m=800kg
L=10000m
v=40m/s

m=200kg
L=5000m
v=120m/s

m=300kg
L=10000m
v=80m/s

Explanation / Answer

For mass m1 = 200 kg, we have

a1 = v12 / L = (160 m/s)2 / (5000 m)

a1 = 5.12 m/s2

For mass m2 = 100 kg, we have

a2 = v22 / L = (160 m/s)2 / (2500 m)

a2 = 10.2 m/s2

For mass m3 = 400 kg, we have

a3 = v32 / L = (80 m/s)2 / (2500 m)

a3 = 2.56 m/s2

For mass m4 = 800 kg, we have

a4 = v42 / L = (40 m/s)2 / (10000 m)

a4 = 0.16 m/s2

For mass m5 = 200 kg, we have

a5 = v52 / L = (120 m/s)2 / (5000 m)

a5 = 2.88 m/s2

For mass m = 300 kg, we have

a6 = v62 / L = (80 m/s)2 / (10000 m)

a6 = 0.64 m/s2

To rank for each satellite based on its acceleration from largest to smallest which will be given as :

a2 > a1 > a5 > a3 > a6 > a4

Related Questions

Navigate

• Browse (All)
• Browse C
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.