Help will be rated. You will submit your work for this problem on paper. You can

Question

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You will submit your work for this problem on paper. You can get (partial) credit so be clear about what you are doing and make your work easy to follow. Vector A has a magnitude of 3 91 m and is directed theta_A = 62.0degree counter- from the + x axis. Vector B has a magnitude of 2.54 m and Is directed theta_B = 11.8^th The angular measures are illustrated here, but note that this image is NOT to scale a. Determine the x and y components of vector A. b. Determine the x and y components of vector B. c Determine the magnitude of A - B This quantity is commonly denoted as |A - B| d Determine the direction of A -B. Measure this angle counter clockwise from the +x axis.

Explanation / Answer

Ax = 3.91 cos 62 = 1.84 m

Ay = 3.91 sin 62= 3.45 m

B x = 2.54 cos168.2 = -2.49 m

By = 2.54 sin 168.2 = 0.519 m

c) Rx = Ax-Bx = 4.33 m

Ry = 2.931 m

magnitude of A-B = sqrt(Rx^2+Ry^2) = 5.228 m

d) direction theta = tan^-1(Ry/Rx) = 34.09 degrees

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