In the circuit below, the input voltage is V_in = V_in peak cos(omega t), R = 20

Question

In the circuit below, the input voltage is V_in = V_in peak cos(omega t), R = 20 K Ohm and C = 15nF. a) Show that the output voltage is V_out = V_Hcos (omega t - delta), where v_H = V_in peak/Squareroot 1 + (omega RC)^-2 b) Show that this result justifies calling this circuit a high-pass filter c) Find an expression for the phase constant delta in terms of R, C and omega d) At what frequency is v_H = (1/Squareroot 2) V_in peak? That particular frequency is known as the 3dB frequency, or f_3dB, of the circuit e) Using Excel, make a graph of log_10(V_H) versus log_10(f), where f is the frequency. Make sure that the scale extends from at least 10% of the 3-dB frequency to ten times the 3-dB frequency f) Make a graph of the phase constant versus log_10(f) for the same range of frequencies as in part e) above g) What is the value of the phase constant when the frequency is equal to the 3-dB frequency?

Explanation / Answer

The value of Vin peak will be given to us. We can't calculate it. Infact we will calculate the rest of the quantities using this value.

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