A 1.1 kg box mows back and forth on a horizontal frictionless surface between tw

Question

A 1.1 kg box mows back and forth on a horizontal frictionless surface between two different springs, as shown in the accompanying figure. The box is initially pressed against the stronger spring, compressing it 3.7 cm, and then is released from rest. (Figure 1) By how much will the box compress the weaker spring? Express your answer in centimeters to two significant figures. Delta t = 2.783 What is the maximum speed the box will reach? Express your answer in meters per second to two significant figures. V_max =

Explanation / Answer

conserving energy

let the compression is x cm

0.5k1*3.7^2=0.5*k2*x^2

k1=32 N/m

k2=16 N/m

we got

x=5.23 cm

Let the maximum speed is v m/s ,Again conserving energy between spring energy and kinetic energy

0.5mv^2=0.5*32*0.037^2

we got v=0.2 m/s

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