block is suspended by a massless A 1.50 block is suspended by a massless string

Question

block is suspended by a massless A 1.50 block is suspended by a massless string that is wrapped around a pulley as shown. The pulley can be considered to be a solid disk with mass 0.750 kg and radius 0.250 m that rotates around its center. The mass is released and begins to move downward. Calculate the linear acceleration of the mass. An object of mass m is on a frictionless table rotating with a given tangential speed v_o with a radius of string r_i. The string goes down through a hole (no friction)

Explanation / Answer

here,

4)

mass , mb = 1.5 kg

m = 0.75 kg , r = 0.25 m

the linear accelration of mass , a = mb * g /( mb + 0.5 * m * r^2 /r^2)

a = 1.5 * 9.81 /( 1.5 + 0.5 * 0.75)

a = 7.85 m/s^2

the linear accelration is 7.85 m/s^2

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