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According to our records you have not yet redeemed an access code for this class or purchased access online. The grace period will and Tuesday. June 20 2017 at 12 00 AM CDT After that dale you will no longer be able to see your WebAssign assignments or grades Get access now. A ball is thrown directly downward with an initial speed of 7.60 m/s, from a height of 30.6 m. After what time interval does it strike the ground? An attacker at the base of a castle wall 3.60 m high throws a rock straight up with speed 8.80 m/s at a height of 1.54 m above the ground. (a) Will the rock reach the top of the wall? Yes No (b) If so, what is the rock's speed at the top? If not, what initial speed must the rock have to reach the top? _ m/s (c) Find the change in the speed of a rock thrown straight down from the top of the wall at an initial speed of 8.80 m/s and moving between the same two points. m/s (d) Does the change in speed of the downward-moving rock agree with the magnitude of the speed change of the rock moving upwards between the same elevations? Explain physically why or why not.

Explanation / Answer

here,

initial speed , u = 7.6 m/s

h = 30.6 m

h = u * t + 0.5 * g * t^2

30.6 = 7.6 * t + 0.5 * 9.81 * t^2

solving for t

t = 1.84 s

the time taken is 1.84 s

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