In the figure four particles are fixed along an x axis, separated by distances d

Question

In the figure four particles are fixed along an x axis, separated by distances d = 3.80 cm. The charges are q1 = +4e, q2 = -e, q3 = +e, and q4 = +12e, with e = 1.60 × 10-19 C. What is the value of the net electrostatic force on (a) particle 1 and (b) particle 2 due to the other particles?

Chapter 21, Problem 046 In the figure four particles are fixed x along an axis, separated by distances d 3.80 cm. The charges are q +4e, q2 the net electrostatic force on (a) particle 1 and (b) particle 2 due to the other particles? (a) Number Units (b) Number Units e, q3 +e, and Q4 12e, with e 1.60 x 19 C. What is the value of

Explanation / Answer

here,

q1 = 4 e

q2 = - e

q3 = e

q4 = 12 e

d = 3.8 cm = 0.038 m

a)

the force on particle 1 , F1 = k * q1 * (q2 /d^2 - q3 /(2d)^2 - q4 /(3d)^2 )

F1 = 9 * 10^9 * 4 * 1.6 * 10^-19 * ( 1.6 * 10^-19 /0.038^2 - 1.6 * 10^-19 /(2 * 0.038)^2 - 12 * 1.6 * 10^-19 /( 3 * 0.038)^2) N

F1 = - 3.72 * 10^-25 N

the force is 3.72 * 10^-25 N towards left

b)

the force on particle 2 , F2 = k * q2 * (- q1 /d^2 + q3 /(d)^2 + q4 /(2d)^2 )

F2 = 9 * 10^9 * 1.6 * 10^-19 * ( - 4 * 1.6 * 10^-19 /0.038^2 + 1.6 * 10^-19 /(0.038)^2 + 12 * 1.6 * 10^-19 /( 2 * 0.038)^2) N

F2 = 0 N

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.