dit View History Bookmarks Window Help 100n Fri 1024 AM Class Management More (1

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dit View History Bookmarks Window Help 100n Fri 1024 AM Class Management More (13%) Problem 2: A 1140 139:00 PM End Date: 1200 00 AM acceleration of 2.2 x 104 kg artill shell is fired from abattleship. While it is in the barrel of the gun, experiences an m/s Randomized Variables m 1140 kg a m 2.2 x 104 m/s2 nment Status k here for ailed view 50% Part b) What is the magnitude of the force exerted on the ship by the artillery shell in Newtons? sin00 4 5 6 cotano asin0 acos Completed atano acotan0 sinh0 Completed Completed oDegrees Radians Completed Completed I give up! Completed Feedback: deductie per feedback Hints: deduction per hint. Hints remaining

Explanation / Answer

Solution:

A)

Force exerted on the shell = F = M.a (Newton's second law)

=> F = 1140 ×2.2×104

=> F = 2.508 ×107 N

B)  The force on the ship = force exerted on the shell (Newton's third law)

but in opposite direction!

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