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Please answer all parts of the question! If you examine your smartphone battery,

ID: 1640917 • Letter: P

Question

Please answer all parts of the question!

If you examine your smartphone battery, you will likely see two numbers: the battery's "capacity" labeled in mAh amps times hours or milliamp-hours), and the battery's voltage or potential difference in V (volts). What physical quantity is the battery's "capacity" measuring? Explain how you can tell. Suppose your phone's battery has a capacity of 2700 mAh and a potential difference of 3.6 V. What is the amount of charge, in C (coulombs), that is stored in your smartphone battery when it's fully charged? Charge = Smartphone chargers are usually labeled with their current output in A (amps). Suppose your charger delivers a current of 1.1 A. If your phone's battery is completely drained, how long will it take to fully charge the battery using your charger? Charging time = hours Smartphones are advertised with a certain amount of "talk time" i.e., how long the phone's battery will last if you are making a call. If your phone is advertised with 24 hours of talk time, what is the average current coming from your phone's battery while making the call? Average current = A What is the average power output of your phone's battery while you're making a call? Average power = W

Explanation / Answer

1. Q= It (where I is the current in Amperes and t is time) so mAh is the unit for charge so the battery capacity can be told as the measure of the charge stored by the battery. Also it tells the maximum energy that can be extracted out of battery under specified conditions.

2. Charge stored = 2700 x 10-3 x 60x 60 = 9720 Coulombs

3. Charging time = Capacity/ Current = 2.7/1.1 = 2.45 Hours

4. Current coming out = capacity/time = 2700/24 = 0.1125 A

5. Power output = IV = 0.1125 x 3.6 = 0.405 Joules.

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