edugen wileyplus.com Physics question | Chegg.com WileyPLUS WileyPLUS: MyWlleyPL

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edugen wileyplus.com Physics question | Chegg.com WileyPLUS WileyPLUS: MyWlleyPLUSI Help | Contact Us I Log Out WileyPLUS Halliday, Fundamentals of Physics, 10,e Calculus-based Physics I & II (PH 201-202) Home Rcad, Study& Practice Assignment Gradebook ORION Assignment>Open Assignment FULL SCREENPRINTER VERSION BACK NEXT ASSIGNMENT RESOURCES HW8 Chapter 08, Problem 071 Chapter 08, Problem 007 In the figure, a block is sent sliding down a frictionless ramp. Its speeds at points A and B are 2.40 m/s and 3.40 m/s, respectively. Next, it is again sent sliding down the ramp, but this time its speed at point A is 4.60 m/s. What then is its speed at point B? 015 024 Chapter 08, Problem 025 031 047 Number Units 098 the tolerance is +/-8% 099 Chapter 08, Problem 102 SHoW HIN LINK TO TEXT Review Score Question Attempts: 0 of 6 used SAVE FOR LATER SUBMIT ANSWER Copyright © 2000-2017 by John Wiley & Sons, Inc. or related companies. All rights reserved. License AgreementPrivacy Policy I2000-2017 John Wiley &Sons;, Inc. All Rights Reserved. A Division af John Wiley & Sans, Inc Version 4.22.4.6

Explanation / Answer

Energy at point A = Energy at Point B

0.5mv1^2 +PE(A) = 0.5mv2^2 + PE(B)

PE(A) -PE(B) = 0.5m(3.4^2 - 2.4^2)

= 2.9 m

For the next time

PE(A) - PE(B) = KE(B) - KE(A)

2.9 m = 0.5mv^2 - 0.5*m*4.6^2

v = 5.2 m/s

so the speed at point B is 5.2 m/s

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