The vector position of a particle varies in time according to the expression Gam

Question

The vector position of a particle varies in time according to the expression Gamma vector = 8.40 I - 7.00t^2 J where Gamma vector is in meters and t is in seconds. (a) Find an expression for the velocity of the particle as a function of time. (Use any variable or symbol stated above as necessary.) v vector = m/s (b) Determine the acceleration of the particle as a function of time. (Use any variable or symbol stated above as necessary.) a vector = m/s^2 (c) Calculate the particle's position and velocity at t = 4.00 s. Gamma vector = m v vector = m/s J

Explanation / Answer

r=8.4i-7t^2j

v=dr/dt=-14tj differentiate r with respect to time

a=-14j differentiate v with respect to time

at t=4s

r=8.4i-7×4×4j=8.4i-112jmagnitude of r wil be ((8.4)^2+(112)^2)1/2 =112.3m

V=-14×4j=-56j magnitude of v wil be =56m/s

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.