solve the following please 6. 1/3 points I Previous Answers KatzPSE1 2.P.033. My
ID: 1642537 • Letter: S
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solve the following please
6. 1/3 points I Previous Answers KatzPSE1 2.P.033. My Note The figure below shows the y-position (in blue) of a particle versus time y (m) 20 16 12 8 4 t (s) (a what is the average velocity of the particle during the time interval t-2.00 s to t = 450 s? Express your answer in vector form, 1.4 m/s (b) Using the tangent to the curve (shown as the orange line in the figure), what is the instantaneous velocity of the particle at t-1.50 s? (Express your answer in vector form.) m/sExplanation / Answer
5 (a) At t1 = 1.75 yr, x1 = (3.00 * 1.752) - (3.75 * 1.75) + 7.00 = 9.625 AU
At t2 = 8.00 yr. x2 = (3.00 * 8.002) - (3.75 * 8.00) + 7.00 = 169 AU
Total distance travelled between t1 and t2 is, x = 169 - 9.625 = 159.375 AU
Average velocity, vavg = x/t = 159.375 / (8.00 - 1.75) = 25.5 Au/yr
(b) Instantaneous speed, v = dx/dt = 6.00t - 3.75
At t1 = 1.75 yr, v1 = (6.00 * 1.75) - 3.75 = 6.75 AU/yr
At t2 = 8.00 yr, v2 = (6.00 * 8.00) - 3.75 = 44.25 AU/yr
(c) v = 6.00t - 3.75 = 0
=> t = 3.75 / 6.00 = 0.625 yr
(NOTE: Only one question is to be done per post according to Chegg's rules. Please post question 6 again independently.)
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