Q9. An electron (m= 9.11*10 -31 and charge q=-1.60*10 -19 C) is inside a paralle

Question

Q9. An electron (m= 9.11*10-31 and charge q=-1.60*10-19 C) is inside a parallel plate capacitor as shown in the figure. The electric field (shown with red arrow) has a magnitude of 2000N/C. The electron is initially at rest. Answer the following questions.

What is the force on the electron (magnitude and direction)?

What is the acceleration of the electron?

Q9. An electron (m= 9.11*10-31 and charge q=-1.60*10-19 C) is inside a parallel plate capacitor as shown in the figure. The electric field (shown with red arrow) has a magnitude of 2000N/C. The electron is initially at rest. Answer the following questions.

What is the force on the electron (magnitude and direction)?

What is the acceleration of the electron?

Explanation / Answer

Given that

electric field E=2000 N/c

mass of electron m=9.11*10^-31 kg

charge q=-1.6*10^-19 C

basing on the concept of intensity of electric field

now we find the force on the electron

force F=Eq=2000*-1.6*10^-19=-3200*10^-19 N

they are repulse force

now we find the acceleration of the electron

acceleration a=Eq/m=-3200*10^-19/9.11*10^-31=-351.3*10^12 m/s^2

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