An air-filled toroidal solenoid has a mean radius of 16.0 cm and a cross-section

Question

An air-filled toroidal solenoid has a mean radius of 16.0 cm and a cross-sectional area of 5.00 cm2 . When the current is 12.0 A , the energy stored is 0.400 J .

How many turns does the winding have? N=

2- A transformer consists of 285 primary windings and 834 secondary windings.

A- If the potential difference across the primary coil is 25.5 V , what is the voltage across the secondary coil? I got 74.6 V

B-

If the potential difference across the primary coil is 25.5 V , what is the current in the secondary coil if it is connected across a 110 resistor?

Express your answer in amperes to three significant figures.

I=____ A

Explanation / Answer

(1) Energy stored in the solenoid is given by
E = (1/2)LI2
where L is inductor and I is current
0.4 = (1/2)*L*(12)2
L = 5.55*10-3 H
We know that L(inductance) of a solenoid is given by
L = uoN2A /(2Pi*R)
where N is no. of turn , A is area of cross-section , R is mean radius
N2 = L*(2Pi*R) / uoA
N2 = (5.55*10-3)*(2Pi*16*10-2) /{(4Pi*10-7)*(5*10-4)}
N = 2979.93
N = 2980 turns (approx)

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