Question 31 of 32 Incorrect Sapling Learning macmillan learning An initially unc

Question

Question 31 of 32 Incorrect Sapling Learning macmillan learning An initially uncharged 4.31 106 F capacitor and a 8290 resistor are connected in series to a 1.50 V battery that has negligible internal resistance. What is the initial current in the circuit? Calculate the circuit's time constant. How much time must elapse from the closing of the circuit for the current to decrease to 3.67% of its initial value? Initial current: Number Time constant: Number Elapsed time: Number Previous Check Answer NexExi Hint

Explanation / Answer

According to the given problem,

a) At t=0 no chagre in capacitor. so, current is present in resistor only,

I0 = V/R = 1.50/8290 = 1.81*10-4A

b) Time contant in a RC circute,

T = RC = 8290*4.31*10-6 = 0.3573 s

c)Using the relation,

I(t) = Io e-t/

0.0367I0 = Io e-t/

t = 1.181 s

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