(8%) Problem 12: Unpolarized light of intensity 10-750 W/m2 is incident upon two

Question

(8%) Problem 12: Unpolarized light of intensity 10-750 W/m2 is incident upon two polarizers. The first has its polarizing axis vertical, and the axis of the second is rotated = 45° from the vertical. Randomized Variables 10 = 750W/ 45° ©theexpertta.com 50% Part (a) what is the intensity of the light after it passes through the first polarizer in Wm Grade Summa Deductions Potential ry 0% 100% sin0 cotan0asin acos0 atan0 acotan) sinhO coshOtanh cotanh0 cosO tan Submissions Attempts remaining:;4 (0% per attempt) detailed view *1 2 3 END Degrees Radians NO Submit Hint Hints: 5% deduction per hint. Hi ints remaining: 2 Feedback: 0% deduction per feedback. 50% Part (b) What is the intensity ofthe light after it passes through the second polarizer in W m

Explanation / Answer

(A) As unpolarized light passes through the polarizer, light becomes polarized along the polarising axis.

and intensity become halved.

I = Io / 2 = 750 / 2 = 375 W/m^2

(b) after that,

If = I (cos(theta))^2

If = (375) (cos45)^2

= 187.5 W/m^2

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