The tractor exerts a towing force T = 400 lb. It has a weight of 6400 lb and a c
ID: 1647738 • Letter: T
Question
The tractor exerts a towing force T = 400 lb. It has a weight of 6400 lb and a center of gravity located at GT. An additinal weight of 600 lb is added to its front having a center of gravity at GA. Take s = 0.4. The front wheels are free to roll.
Determine the normal reactions at each of the two front tires.
Determine the normal reactions at each of the two rear tires.
Determine the tractive frictional force F on each rear tire needed to pull the load forward at constant velocity.
QGA 2.5 ft CL F 3 ftExplanation / Answer
2 B X 9 + 400 X 2.5 - 6400 X 5 - 600 X 12 = 0
18 B = 38200
B = 38200 / 18
B = 2122.22 lb
B = 2.1222 kip
and
2 C + 2 X 2122.22 - 6400 - 600 = 0
C = 2755.56 / 2
C = 1377.78 lb
C = 1.37778 kip
and
2 F - 400
F = 200 lb
Fmax = s NC
= 0.4 X 1377.78
Fmax = 551.112 lb
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