If half the weight of a flatbed truck is supported by its two drive wheels, what

Question

If half the weight of a flatbed truck is supported by its two drive wheels, what is the maximum acceleration it can achieve on dry concrete where the coefficient of kinetic friction is 0.7 and the coefficient of static friction is 1. B) will a metal cabinet lying on the wooden bed of the truck slip if it accelerates at a rate we are the coefficient of kinetic friction is 0.3 and the coefficient of static friction is 0.55? If half the weight of a flatbed truck is supported by its two drive wheels, what is the maximum acceleration it can achieve on dry concrete where the coefficient of kinetic friction is 0.7 and the coefficient of static friction is 1. B) will a metal cabinet lying on the wooden bed of the truck slip if it accelerates at a rate we are the coefficient of kinetic friction is 0.3 and the coefficient of static friction is 0.55? If half the weight of a flatbed truck is supported by its two drive wheels, what is the maximum acceleration it can achieve on dry concrete where the coefficient of kinetic friction is 0.7 and the coefficient of static friction is 1. B) will a metal cabinet lying on the wooden bed of the truck slip if it accelerates at a rate we are the coefficient of kinetic friction is 0.3 and the coefficient of static friction is 0.55?

Explanation / Answer

According to the given problem,

A) a = net force / mass = µ*mg/2 / m = µg/2
a = 1.0 * 9.8m/s² / 2 = 4.9 m/s²

B) Yes, since 0.55 < 1.0

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